The fun side of Math
100 - 
27639 pts ★ Legend
5548 pts ★ NoviceOn 2025-02-09 at 22:42:43
Edit: Basically just talk about whatever interesting math puzzles and stuff you want, but
DO NOT MAKE FUN OF MATH OR I WILL HATE YOU(srsly. Do not do it. Don't even think of doing it.)
Hello everyone! This topic will be about sharing math puzzles and things related to math! (Integration, quad formula, etc.)
Puzzle 1:
You are rowing a boat at 4.2 mph relative to the river. From the boat you launch a paper boat at 1:32 PM. The river's current is 2.6 mph relative to the ground. You row downstream at 2:14 PM. When will you be able to retrieve the paper boat?
For @NeverCookAgain:
Imaginary numbers are numbers that are multiples of i. If i were not a number, then:
Let's solve x^2 + 3x + 9 = 0
Use the quad formula(a = 1):
(-3 +- sqrt(3^2 - 4*9))/2
(-3 +- sqrt(-11))/2 Oh no
-1.5 +- sqrt(-11)/2
We did not allow i to be a number, so we conclude that the equation has no solutions. If i were a number then x = [-1.5 + 5.5i, -1.5 - 5.5i]
Perhaps a coordinate grid, with the x-axis as regular numbers(pi, 99, e) and the y-axis as imaginary numbers(i, 2i) would help. The point (2, 1) would have a value of 2 + i.
(5, 2) + (7.5, 1) = 12.5 + 3i
Maybe I'll explain j and k later.
DO NOT MAKE FUN OF MATH OR I WILL HATE YOU(srsly. Do not do it. Don't even think of doing it.)
Hello everyone! This topic will be about sharing math puzzles and things related to math! (Integration, quad formula, etc.)
Puzzle 1:
You are rowing a boat at 4.2 mph relative to the river. From the boat you launch a paper boat at 1:32 PM. The river's current is 2.6 mph relative to the ground. You row downstream at 2:14 PM. When will you be able to retrieve the paper boat?
For @NeverCookAgain:
Imaginary numbers are numbers that are multiples of i. If i were not a number, then:
Let's solve x^2 + 3x + 9 = 0
Use the quad formula(a = 1):
(-3 +- sqrt(3^2 - 4*9))/2
(-3 +- sqrt(-11))/2 Oh no
-1.5 +- sqrt(-11)/2
We did not allow i to be a number, so we conclude that the equation has no solutions. If i were a number then x = [-1.5 + 5.5i, -1.5 - 5.5i]
Perhaps a coordinate grid, with the x-axis as regular numbers(pi, 99, e) and the y-axis as imaginary numbers(i, 2i) would help. The point (2, 1) would have a value of 2 + i.
(5, 2) + (7.5, 1) = 12.5 + 3i
Maybe I'll explain j and k later.
On 2025-02-09 at 22:48:33
It's the weekend, I'm not doin' math!
Edit: This is old stop reacting pls
Edit: This is old stop reacting pls
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1On 2025-02-09 at 23:10:35
I'll answer you sometime on a weekday, bro.
Edit: Somewhere between 3:00 and 4:00? Sorry for taking so long. It's Tuesday.
To Fiery: Bro, you can't stop swearing for 5 minutes???
Edit: Somewhere between 3:00 and 4:00? Sorry for taking so long. It's Tuesday.
To Fiery: Bro, you can't stop swearing for 5 minutes???
On 2025-02-09 at 23:18:08
What the actual heil is this
1On 2025-02-10 at 00:29:56
On 2025-02-10 at 01:49:40
111111111*111111111=12345678987654321
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On 2025-02-10 at 02:41:47
Hello everyone! This topic will be about sharing math puzzles and things related to math! (Integration, quad formula, etc.)
Puzzle 1:
You are rowing a boat at 4.2 mph relative to the river. From the boat you launch a paper boat at 1:32 PM. The river's current is 2.6 mph relative to the ground. You row downstream at 2:14 PM. When will you be able to retrieve the paper boat?
For @NeverCookAgain:
Imaginary numbers are numbers that are multiples of i. If i were not a number, then:
Let's solve x^2 + 3x + 9 = 0
Use the quad formula(a = 1):
(-3 +- sqrt(3^2 - 4*9))/2
(-3 +- sqrt(-11))/2 Oh no
-1.5 +- sqrt(-11)/2
We did not allow i to be a number, so we conclude that the equation has no solutions. If i were a number then x = [-1.5 + 5.5i, -1.5 - 5.5i]
Perhaps a coordinate grid, with the x-axis as regular numbers(pi, 99, e) and the y-axis as imaginary numbers(i, 2i) would help. The point (2, 1) would have a value of 2 + i.
(5, 2) + (7.5, 1) = 12.5 + 3i
Maybe I'll explain j and k later.
Puzzle 1:
You are rowing a boat at 4.2 mph relative to the river. From the boat you launch a paper boat at 1:32 PM. The river's current is 2.6 mph relative to the ground. You row downstream at 2:14 PM. When will you be able to retrieve the paper boat?
For @NeverCookAgain:
Imaginary numbers are numbers that are multiples of i. If i were not a number, then:
Let's solve x^2 + 3x + 9 = 0
Use the quad formula(a = 1):
(-3 +- sqrt(3^2 - 4*9))/2
(-3 +- sqrt(-11))/2 Oh no
-1.5 +- sqrt(-11)/2
We did not allow i to be a number, so we conclude that the equation has no solutions. If i were a number then x = [-1.5 + 5.5i, -1.5 - 5.5i]
Perhaps a coordinate grid, with the x-axis as regular numbers(pi, 99, e) and the y-axis as imaginary numbers(i, 2i) would help. The point (2, 1) would have a value of 2 + i.
(5, 2) + (7.5, 1) = 12.5 + 3i
Maybe I'll explain j and k later.
nah bro wth dawg damn son who is einstein on this site
On 2025-02-10 at 08:37:11
fuck you mean mariofacepalm how was anyone here supposed to know it was a reference to an obscure 2 year old topic besides krazey who hates imaginary numbers which also why the hell was this made if the guy don’t like imaginary numbers? swear down this so confusing
On 2025-02-10 at 23:11:42
This is not going well. I'll lock this topic. (Sorry)
I'll answer all the questions here.
@ChilledIce
Me and @Pigouni64
@MovieSonic623
That is not true. How could you.
@Fiery
1. Please stop swearing
2. I just have to explain math 'cus I like math.
3. It's 1 year old(October or something of 2023. It's February.)
And @jmeme:
This is actually correct! For numbers with only 1s, and less than 10 digits long, x^2 follows the pattern:
1
121
12321
1234321
And so on.
Edit: If enough people react with :genius: then maybe I'll unlock this. Probably not.
I'll answer all the questions here.
@ChilledIce
Me and @Pigouni64
@MovieSonic623
That is not true. How could you.
@Fiery
1. Please stop swearing
2. I just have to explain math 'cus I like math.
3. It's 1 year old(October or something of 2023. It's February.)
And @jmeme:
This is actually correct! For numbers with only 1s, and less than 10 digits long, x^2 follows the pattern:
1
121
12321
1234321
And so on.
Edit: If enough people react with :genius: then maybe I'll unlock this. Probably not.
2
14
1
On 2025-02-10 at 23:55:45
This is not going well. I'll lock this topic. (Sorry)
I'll answer all the questions here.
@ChilledIce
Me and @Pigouni64
@MovieSonic623
That is not true. How could you.
@Fiery
1. Please stop swearing
2. I just have to explain math 'cus I like math.
3. It's 1 year old(October or something of 2023. It's February.)
And @jmeme:
This is actually correct! For numbers with only 1s, and less than 10 digits long, x^2 follows the pattern:
1
121
12321
1234321
And so on.
Edit: If enough people react with :genius: then maybe I'll unlock this. Probably not.
I'll answer all the questions here.
@ChilledIce
Me and @Pigouni64
@MovieSonic623
That is not true. How could you.
@Fiery
1. Please stop swearing
2. I just have to explain math 'cus I like math.
3. It's 1 year old(October or something of 2023. It's February.)
And @jmeme:
This is actually correct! For numbers with only 1s, and less than 10 digits long, x^2 follows the pattern:
1
121
12321
1234321
And so on.
Edit: If enough people react with :genius: then maybe I'll unlock this. Probably not.
I deleted my message, I guess I didn't read the instructions when I posted it
On 2025-03-02 at 22:18:08
Finally this topic is unlocked! Math is useful, but I don't really know how it's fun. I guess I gotta make it actually fun. The only way it's fun is that it's easy. I have no equation sadly.
1On 2025-03-02 at 22:29:58
Can you hit an opponent with a green shell without missing while in a glider?
Answer: Yes. Aim at [blank] above the opponent's head and you will hit him.
What angle am I talking about?
Answer: Yes. Aim at [blank] above the opponent's head and you will hit him.
What angle am I talking about?
On 2025-03-02 at 22:40:30
Can you hit an opponent with a green shell without missing while in a glider?
Answer: Yes. Aim at [blank] above the opponent's head and you will hit him.
What angle am I talking about?
Answer: Yes. Aim at [blank] above the opponent's head and you will hit him.
What angle am I talking about?
Aim at the angle that has the slope of the tangent of the quadratic equation where the length of the curve from 0 to m is equal to the opponent's time took to reach m multiplied by the ratio of the shell's speed to the opponent's kart speed. This answer assumes that the speed that the shell travels does not depend on the kart speed. This also assumes that your x = 0 and your y = the quad equation at x=0.
On 2025-03-02 at 22:41:34
1+1=11
On 2025-03-02 at 22:46:09
1+1=11
Unless you're talking about place value, 1+1=2
If you're talking about place value, you are correct!
On 2025-03-02 at 22:47:11
1+1=11
OUT WITH IT! DID YOU NOT READ MY EDIT???
Delete your message now, okay?
I said to not make fun of math.
On 2025-03-02 at 23:11:32
What is 1+2+3+4+5+6+7+8+9+10
Watch this video to find out https://youtu.be/dQw4w9WgXcQ?si=H0DPGjHiQZSRcacW
11